Question

a bullet of mass 0.05 kg has a speed of 400 m/s. If the bullet hits a wall and goes through the wall which has an average resistance of 10,000 N, calculate the distance of penetration by the bullet.

Answer 1

Hello friend...!!

⇒ according to the question, we should calculate the distance penetrated by the bullet into the block 

given that :

⇒ u = 150 m/s

⇒ v = 0 

⇒ t = 0.03 sec 

⇒ m = 10 g = 0,01 Kg

we know that , S = ( v² - u²) / 2a  ------------( 1 )

we should calculate acceleration ,  v = u + at 

a =  ( v - u ) / t

a = ( 0 - 150 ) / 0.03

a = -5000 m/s² ---------------( 2 ) 

substituting equation ( 2 ) in ( 1 ) gives ,

S = { 0 - (150)² } / - ( 2 x 5000 )

S= 22500 / 10000

S = 2.25 m 

therefore, the distance penetrated by the bullet is 2.25 m

to calculate force ,we know

F = m x a 

⇒ F = 0.01 x 5000

⇒ F = 50 N 

the force exerted by the wooden block on the bullet  is 50 N 

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hope it helps..!!

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