Question

a bullet of mass 0.05 kg is fired from a gun of mass 3 kg with a velocity of 200 m/s the recoil velocity of the gun is​

Answer 1

Answer:

a bullet of mass 0.05 kg is fired from a gun of mass 3 kg with a velocity of 200 m/s the recoil velocity of the gun is 0.53 m/s

Answer 2

Answer:

A bullet of mass 0.05 kg is fired from a gun of mass 3 kg with a velocity of 200 m/s the recoil velocity of the gun is​ 3.3333 m/s.

Explanation:

We know,

Momentum (p)  =  mass (m)  $\times$  velocity (v)

Given,

Mass of the bullet  ( $m_{1}$ )  =  0.05 kg

Mass of the gun     ( $m_{2}$ )  =  3 kg

velocity of bullet     ( $v_{1}$ )   =  200 m/s

Let recoil velocity of gun be $v_{2}$ ,

Then,

The momentum of bullet  =  $m_{1} v_{1}$

The momentum of gun     =  $m_{2}v_{2}$

According to the law of conservation of momentum,

Momentum of the bullet   =  momentum of the gun

That is,

$m_{1} v_{1} = m_{2}v_{2}$

$v_{2} = \frac{m_{1}\ v_{1}}{m_{2}}$

$v_{2} = \frac{0.05\times200}{3}$

     = 3.3333 m/s

Ans :

Recoil velocity of the gun = 3.3333 m/s