Question

A bullet of mass 0.05 kg is travelling with initial.
velocity 4oom/s is penetrates into a wall with an
average for 4×10⁴N it goes out of the wall with
a velocity of 50m/s. What is the thickness of wall?
Another bullet of to lower mass but travelling
with same velocity but excerting same force
cannot escape from the wall what is its maximum
mass ?​

Answer 1

Answer:

9.84 cm ,  0.0492 kg

Explanation:

a = F/m =  4×10⁴/ 5×10-² = 8×10^5

thickness = (u² - v²) /2a = (400² - 50²)/16×10^5m. = 9.84 cm.

2nd. question

u²/2a = 400²/2a = 0.0984 , a = 400²/0.1968

maximum mass = f/a = 4×10⁴×0.1968/400² = 0.1968/4 = 0.0492 kg