Question

a bullet of mass 0.05 moving with a speed of 90 m/s enters a heavy wooden block & is stopped after distance of 60 cm. What is the average resistivity exerted by wooden block on the bullet

Answer 1

By conservation of energy law work done by the force is equal to the change in the kinetic enery
F*d = 1/2*m*v2
F = 1/2*0.05*90*90/0.6=81*5/1.2=4050/12=337.5N