Question

A bullet of mass 0.1 kg is fired with a speed of 100m/s.The mass of the gun being 50kg.The velocity of the recoil is

Answer 1

Answer:

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Answer 2

Answer:

The velocity of the recoil of the gun will be equal to 0.2m/s.

Explanation:

Given bullet has mass,  $m_{1}=0.1kg$

Initially Speed of the bullet,  $u_{1}=0$

Final speed of the bullet, $v_{1}=0$

Given the mass of the gun, $m_{2}= 50kg$

Initially Speed of the gun, $u_{2}=0$

We have to find final speed of the gun ($v_{2}$):

From the law of the conservation of the momentum:

⇒    Initial momentum = Final momentum

⇒         $m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\ (0.1)(0)+(50)(0)=(0.1)(100)+(50)(-v_{2})$

⇒                          $0=10-50v_{2}\\ v_{2}=\frac{10}{50}$

       ∴                   $v_{2}=0.2ms^{-1}$    

Therefore after firing the bullet, the gun recoils with the velocity 0.2m/sec.