Question

A bullet of mass 0.1 kg is fired with a velocity of 100m/s .what is its K.E?....

plzz tell me the answer , it's urgent ​

Answer 1

Explanation:

R

⇒ u = 100 m/s

⇒ v = 0 m/s

⇒ g = - 10 m/s²

we should find the approximate time taken to reach the ground

so , we know that ,

v = u - gt

implies ,

t = v - u / -g

t = 0 - 100 / - 10

t = 10 seconds .

therefore the approximate time taken to reach the ground is 10 s + 10s = 20s seconds.

Answer 2

Explanation:

$mass =0.1kg \\ velocity = 100mps \\ kinetic \: \: energy = \frac{mass \times velocity {}^{2} }{2} = \frac{0.1 \times 100 \times 100}{2} = 500 \: \: joule \: \: \: \: ans.$

Hope it will help you.