Question

A bullet of mass 0.10 kg travels horizontally at a speed of 600 m/s. It strikes a stationary wooden block of mass 1.90 kg resting on a frictionless, horizontal surface. The bullet stays in the block. What is the speed of the bullet and the block immediately after the impact?

Answer 1

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Answer 2

Given :

Mass of bullet , m = 0.10 kg .

Speed of bullet , $u_b=600\ m/s$ .

Mass of wooden block , M = 1.9 kg .

To Find :

The speed of the bullet and the block immediately after the impact .

Solution :

We know , by conservation of momentum .

Initial momentum = Final momentum

$mu_b+Mu_w=v(m+M)\\\\0.1\times 600+1.9\times0=v(0.1+1.9)\\\\60=v(2)\\\\v=30\ m/s$

Therefore , the speed of the bullet and the block immediately after the impact is 30 m/s .

Learn More :

Conservation Of Momentum

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