Physics, asked by Mohdarbaaz, 1 year ago

a bullet of mass 0.1kg moving horizontally with a velocity of 20m/s strikes a stationary target & is brought to rest in 0.1s. find the impulse & average force of impact.

Answers

Answered by naveenyes2000
1
impulse = 0.1*20*0.1 = 0.2
avg force =F(imp)/t=2
Answered by Anonymous
3
From Newton's second law of motion, we have established that the force that acts on a body can be calculated by using the formula:

F = ma

Where F stands for force; m for the mass of the body, and a the acceleration of the body.

From the formula for force above, to calculate the force that acts on a body, we simply multiply its mass, which is measured in kilogram (kg) with its acceleration measured in metre per second squared (ms-2).

The acceleration of a body is the rate of change in its velocity. Stating it in mathematical term:

Acceleration (a) = ∆v/t.

The symbol ∆ is called delta, and it represents a change in the value of a property.  ∆v therefore stands for a change in velocity.

∆v = displacement / time 

Therefore, acceleration = displacement/t2 and this is why the SI unit of acceleration is metres per second squared. 

Hence, another way of stating the formula for force is:

Force = mass x displacement/time2

The SI unit of force is the Newton (N). This means that after you have calculated the quantity of force on a body, you must express it in Newtons.

Remember that in physics calculations, all quantities are expressed in their respective units.

Similar questions