a bullet of mass 0.2 kg is fired from gun weighing 7.5kg. if the initial velocity of the bullet is 200ms,calculate the speed with which the gun reciols
Answers
Answer :
Mass of bullet = 0.2kg
Mass of gun = 7.5kg
Speed of bullet = 200m/s
We have to find recoil speed of gun
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In case of bullet firing from gun, total momentum of whole system is conserved since no net force acts on the system.
Initial momentum of system = zero
Therefore final momentum of system must be zero.
➝ Final momentum = 0
➝ MV + mv = 0
➝ V = -mv/M
V denotes recoil speed of gun
M denotes mass of gun
m denotes mass of bullet
v denotes speed of bullet
➝ V = -mv/M
➝ V = -(0.2 × 200)/7.5
➝ V = -40/7.5
➝ V = -5.33m/s
[Note : -ve sign shows opposite direction]
Answer:
Mass of bullet = 0.2kg
Mass of gun = 7.5kg
Speed of bullet = 200m/s
We have to find recoil speed of gun..
_________________________________
In case of bullet firing from gun, total momentum of whole system is conserved since no net force acts on the system.
Initial momentum of system = zero
Therefore final momentum of system must be zero.
➝ Final momentum = 0
➝ MV + mv = 0
➝ V = -mv/M
V denotes recoil speed of gun
M denotes mass of gun
m denotes mass of bullet
v denotes speed of bullet
➝ V = -mv/M
➝ V = -(0.2 × 200)/7.5
➝ V = -40/7.5
➝ V = -5.33m/s
[Note : -ve sign shows opposite direction]