A bullet of mass 0.5 kg and moving with a velocity 100m/s is stopped with in 0.1m of target. Find the average distance offered by the target
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Answer:
417N
Explanation:
`u=100m//s` , `u=0` , `s=0.06m` .
Retardation `=a(u^(2))/(2_(s))=((100)^(2))/(2xx0.06)=(1xx10^(6))/(12)` .
:. Force `=ma=(5xx10^(-3)xx1xx10^(6))/(12)=(5000)/(12)=417N` .
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