Question

A bullet of mass 0.5 kg slows down from a speed of 5 m/s to that of 3 m/s. Calculate the change in kinetic energy of that ball.

Answer 1

Referred to the attachments.....

Answer 2

$\huge\red{\mathfrak{Answer}}$

$M= \: mass \: = 0.5kg \\ v = initial \: velocity = 5 \: m/s\\ u = final \: velocity = 3 \: m/s \\ \\ Change \: in \: kietic \: energy \: = \: \frac{1}{2} = m( {v}^{2}_{f} - {v}^{2} - _{i}) \\ \\ \frac{1}{2} \times 0.5 \times 9 - \frac{1}{2} \times 0.5 \times 25 \\ \\ = 2.25 - 6.25 \\ \\ = > 4kg/ {s}^{2}$

Therefore, 4 Joule

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