Question

A bullet of mass 1 gram moving with a speed of 100 m/s enters into a wooden block and

gets stopped after a distance of 1 m. Calculate the force exerted by the wooden block on

the bullet.​

Answer 1

Answer:

Given,

m=0.04kg

u=90m/s

v=0m/s

S=60cm

From 3rd equation of motion,

2aS=v

2

−u

2

a=−

2S

u

2

a=−

2×60×10

−2

90×90

=−6750m/s

2

The resistive force, f=ma

f=−0.04×67.5

f=−270N

Answer 2

Answer:

f = v/t

Explanation:

f =100/1

f =100..

thank you