Question

A bullet of mass 10 g is fired at a speed of 10m/s from a gun of mass 4kg.What is the recoil velocity of the gun?
pls give step by step​

Answer 1

Answer:

1.6 m/s opposite to the direction of the bullet

Let velocity of gun is v.

There is no external force acting, so linear momentum will conserve.

Before the firing, Linear Momentum =0

After the firing, Linear momentum =0.04×400+10×v

⇒0.04×400+10×v=0 ⇒v=−1.6m/s

Hence, 1.6m/s opposite to the direction of the bullet.

Explanation:

literally this questions is simple bro

Answer 2

Answer:

The recoil velocity of the gun is 1 m/s.

Explanation:

Given that,

Mass of bullet = 10 g

Velocity = 400 m/s

Mass of gun = 4 kg

We need to calculate the recoil velocity

Using conservation of momentum,

mb vb =m gv

Where, m_{b}m b =mass of bullet

m_{g}m g=mass of gun

v_{b}v b =speed of bullet

Put the value into the formula

10\times10^{-3}\times400=4\times v10×10

−3×400=4×v

v=\dfrac{10\times10^{-3}\times400}{4}v=

4

10×10−³×400

v=1\ m/sv=1 m/s