A bullet of mass 10 g is fired at a speed of 200 m/s from a gun of mass 4 kg. What is the recoil velocity of the gun?
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Hey mate ur answer,
Step-by-step explanation:
Given, m1(bullet) =10g =0.10 kg
m2 (gun) =4 kg
u1 = 0 m/s
u2 = 0 m/s
v1 = 200 m/s
v2 =?
m1u1+m2u2 =m1v1 +m2v2
0.10 × 0 + 4 kg × 0 = 0.10 × 200 + 4 kg × v
0 = 20 + 4v
- 20 = 4v
-20 /4 =v
-5 = v
therefore the recoil velocity of the gun is -5 m/s.
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