Question

A bullet of mass 10 g is fired horizontally with a velocity of 60m/s from a pistol
mass 1.2 kg What is the magnitude of recoil velocity of the pistol?​

Answer 1

Given that,

• Mass of the bullet (M1) = 10 g

• Velocity of the bullet (V1) = 60 m/s

• Mass of the pistol (M2)= 1.2 kg {convert kg to g} we get 1.2 kg = 1200 grams.

• Recoil velocity of the pistol = ? (V2)

According to the law of conversion of momentum,

         {∵ M1×V1 = M2×V2}

By substituting the value in the formula we get,

⇒ 10g×60m/s = 1200g×M2

⇒ 10g×60m/s/1200g = M2

⇒ 1/2m/s = M2 {Convert m into cm. 1m = 100cm}

⇒ 1/2×100cm/s  = M2

⇒ 50 cm/s = M2

∴ The recoil velocity of the pistol is 50 cm/s.

Hope this helps you.

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