A bullet of mass 10 g is fired with a velocity 72 km/h into a block of mass 1 kg. What is the K.E. of the system?
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By conservation of momentum, we know,
m1v1 =m2v2
10 / 1000 kg × v = =1kg×5m/s
v=1kg×5m/s
10 kg
1000
Velocity of muzzel =V=500m/s
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