A bullet of mass 10 g is fired with a velocity of 400 m/s from a gun of mass 4 kg. What is the recoil velocity of the gun?
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Answered by
5
Here no external force is acted (neglect air resistant) hence momentum of system(gun+bullet) is conserved
initial momentum = finial momentum
let the recoil velocity of gun = v
0.01*0 + 4*0 = 0.01*400 + 4*v
v = -1m/s
hence gun recoil with velocity 1m/s ☺️
initial momentum = finial momentum
let the recoil velocity of gun = v
0.01*0 + 4*0 = 0.01*400 + 4*v
v = -1m/s
hence gun recoil with velocity 1m/s ☺️
Answered by
15
Given: -
▶M1 = 4kg (mass of gun)
▶M2= 10g =0.010kg (mass of bullet)
▶V1=? ( velocity of gun)
▶V2=400m/s (velocity of bullet)
▶M1 × V1=M2 × V2
▶4 × V1=0.010 × 400
▶V1=4/4
▶V1=1m/s
Recoil velocity of the gun =1m /s
HOPE IT HELPS YOU
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▶M1 = 4kg (mass of gun)
▶M2= 10g =0.010kg (mass of bullet)
▶V1=? ( velocity of gun)
▶V2=400m/s (velocity of bullet)
▶M1 × V1=M2 × V2
▶4 × V1=0.010 × 400
▶V1=4/4
▶V1=1m/s
Recoil velocity of the gun =1m /s
HOPE IT HELPS YOU
⛧⛧⛧⛧⛧⛧⛧⛧⛧⛧⛧
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