A bullet of mass 10 g is fired with a velocity of 400m/s from a hun of mass 4 kg. What is the recall velocity of the gun
Answers
Answered by
2
By Applying Law of conservation of momentum,
= M1V1 = M2V2
4 * V1 = 0.01 * 400
4 * V1 = 4
V1 = 1
Recoil velocity of the gun = 1 m/s.
Hope this helps!
= M1V1 = M2V2
4 * V1 = 0.01 * 400
4 * V1 = 4
V1 = 1
Recoil velocity of the gun = 1 m/s.
Hope this helps!
Answered by
1
Initial momentum = 0
Final momentum = 0.01*400 + 4v
Momentum is conserved
0 = 4 + 4v
v = -1 m/s
(-ve becuase gun moves in opposite direction of bullet)
Recoil velocity of gun is 1 m/s
Final momentum = 0.01*400 + 4v
Momentum is conserved
0 = 4 + 4v
v = -1 m/s
(-ve becuase gun moves in opposite direction of bullet)
Recoil velocity of gun is 1 m/s
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