Question

a bullet of mass 10 g is fried from a gun of mass 6kg with the velocity 300m/s. calculate the recoil velocity of the gun.

Answer 1

Initial momentum of the system including the gun and the bullet = 0 


Final momentum of the system = momentum of the gun + momentum of the bullet = Mv/ + mv 


(v/ is the recoil velocity of the gun) 


Applying conservation of linear momentum, 


0 = Mv/ + mv 


Implies, v/ = -(mv)/M


The negative sign indicates that the direction of velocity of the gun is opposite to the direction of velocity of the bullet.

m =10g =0.01kg

mass of gun M= 6kg

velocity of bullet = 300m/s

v/ = -(mv)/M

   = -(0.01 * 300)/6

  = 3/6= -0.5 m/s

Answer 2

Heya..!

to slove such kind of questions use a simple formula..

momentum before the collision = momentum after the collision

you might be already knowing that momentum is the product of mass and velocity.

NOTE: -ve SIGN IN THE ANSWER INDICATES, GUN RECOILS IN OPPOSITE DIRECTION.

HOPE THIS HELPS YOU ❤
BE BRAINLY ✌