Question

A bullet of mass 10 g is shot from a gun of mass 2 kg such that gun recoils with velocity 2 m/a. The bullet strikes a stationary block of mass 490 g placed on a rough horizontal surface and gets embedded in it. If frictional force provided by the surface on black is 2 N. The distance travelled by block before coming to rest is​

Answer 1

Answer:

500m/s.

Explanation:

Conservation of linear momentum gives,

m

1

v

1

+m

2

v

2

=0

m

1

v

1

=−m

2

v

2

v

1

=

m

1

−m

2

v

2

Given, m

1

=10g=(

1000

10

)kg,

m

2

=1 kg,

v

2

=−5m/s

∴v

1

=

10/1000

+1×5

or v

1

=500m/s.