Question

A bullet of mass 10 g moving horizontally with speed of 500 m/s passes through a

block wood of mass 1 kg, initially at rest on frictionless surface. The bullet comes

out of the block with a speed of 200 m/s. The final speed of the block is...? ​

Answer 1

Answer:

μ = 0.16

Step-by-step explanation:

Mass of bullet , m = 0.02 kg

Initial velocity of bullet , v₁ = 500 m/s

Mass of block , M = 10 kg

Initial velocity of block , v₂ = 0

Final velocity of bullet , v₁' = 100 m/s

Let the final velocity of block when bullet comes out , if block = v'

mv₁ + Mv₂ = mv₁' + Mv'

0.02 x 500 = 0.02 x 100 + 10 x v'

v' = 0.8 m/s

After moving a distance 0.2 m it stops .

Change in Kinetic Energy = Work done

0 - (1/2) x 10 x (0.8)² = -μ x 10 x 10 x 0.2

μ = 0.16

Hope it helps!