Question

A bullet of mass 10 g moving horizontally with speed of 500 m/s passes through a
block wood of mass 1 kg, initially at rest on frictionless surface. The bullet comes
out of the block with a speed of 200 m/s. The final speed of the block is
A) 500 m/s B) 300 m/s C) 200 m/s D) 3 m/s

Answer 1

we know that velocity=500m/s,mass of the bullet=0.01 kg

momentum of the bullet before hitting= 500*0.01=5kgm/s

momentum after the penetration= 200*0.01=2kgm/s

change in momentum= final momentum- initial momentum

change in momentum=5-2=3kgm/s

from the law of conservation of momentum

change in momentum= momentum transferred into second object

momentum of the block =3kgm/s

mass of the block=1kg

we know that momentum= mass * velocity

3kgm/s=1*velocity of block

velocity of the block = 3m/s

hope it helps please mark it as brainliest

Answer 2

Answer:

answer I got is 2.5 m/s

Explanation:

I got it ...