Question

A bullet of mass 10 g moving with a speed of 1.5 m/s gets embedded in a & stationary wooden block of mass 90 g. Find the speed attained by the block​

Answer 1

Answer:

The answer that you are looking for is :0.15ms power -1

Explanation:

• Mass of the bullet, m=10 gm=0.01 kg

• Velocity of bullet , v=1.5 ms  

              −1

 

• Mass of plank, m  

p

​

=90 gm=0.09 kg

Initial velocity of plank =0m/s  

Momentum of the bullet, p=mv=0.01×1.5=0.015 kgm/s

Total mass of the plank =m+mp  

​

=0.01+0.09=0.1 kg

∴0.015=0.1×v

⇒∴v=  

0.1

0.015

​

=0.15m/s

The speed of the plank containing the bullet is 0.15m/s