A bullet of mass 10 g moving with a speed of 1.5 m/s gets embedded in a & stationary wooden block of mass 90 g. Find the speed attained by the block
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Answer:
The answer that you are looking for is :0.15ms power -1
Explanation:
- Mass of the bullet, m=10 gm=0.01 kg
- Velocity of bullet , v=1.5 ms
−1
- Mass of plank, m
p
=90 gm=0.09 kg
Initial velocity of plank =0m/s
Momentum of the bullet, p=mv=0.01×1.5=0.015 kgm/s
Total mass of the plank =m+mp
=0.01+0.09=0.1 kg
∴0.015=0.1×v
⇒∴v=
0.1
0.015
=0.15m/s
The speed of the plank containing the bullet is 0.15m/s
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