Question

A bullet of mass 10 g moving with a speed of 20 m/s hits an ice block of mass 990 g kept on a frictionless floor and gets stuck in it. How much ice will melt if 50% of the lost ke goes to ice? (initial temperature of the ice block and bullet = 0c)

Answer 1

"Answer: The bullet has melted 0.003 g of ice.

Given,

Mass of the bullet

=10g = 10 *(10)-3(conversion)

Speed of the bullet = 20 m/s

Mass of the ice = 990 g

Energy required to melt ice = 50% of kinetic energy

Total kinetic energy required

=1/2m(v)2

=1/2*10*(10)-3*(20) 2

Total kinetic energy = 2 J

50% of total kinetic energy

20*50/100

50% of total kinetic energy = 1 J

In this case, the latent heat is amount of heat required to solid (ice) into water.

Latent heat of ice = 334 J/g

Amount of energy required to convert x g of ice,

Kinetic energy = mass * latent heat

1J = x g * 334J/g

x = 1/334

x= 2.9 * (10)-3 = 0.003 g

The bullet has melted 0.003 g of ice."

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