Question

a bullet of mass 10 g moving with a velocity of 400m per s gets empledded in a free suspended wooden block of mass 900g velocity acquired by the block? explain step by step​

Answer 1

Answer:

Here, Mass of the bullet,

<br>

kg <br> =0.01 kg <br> And, Velocity of the bullet,

=400 m/s <br> So, Momentum of bullet=

<br>

…….(1) <br> Now, this bullet of mass 10 g gets embedded into a wooden block of mass 900 g . So ,the mass of wooden blockk alongwith the embedded bullet will become 900+10=910 g. Thus, <br> Mass of wooden block+Bullet,

<br> =910 g <br>

kg <br> =0.91 kg <br> And, Velocity of wooden block+bullet,

(To be calculated) <br> So, Momentum of wooden block+bullet=

<br>

kg.m/s...(2) <br> Now, according to the law of conservation of momentum, the two momenta as given by equations (1) and (2) should be equal. <br> So,

<br> or 0.01

<br> And,

<br> =4.4 m/s <br> Thus, the velocity acquired by the wooden block (having the bullet embedded in it) is 4.4 metres per second.

Explanation:

hope this will help you

please mark me as brainliest

Answer 2

see at the end.

We are given that a bullet of mass 10 g moving with a velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900 g.

Let the final velocity acquired by the block be 'v m/s'.

The mass of the bullet = = 10 g =

= 0.01 kg

The mass of the wooden block = = 900 g =

= 0.9 kg

Also, the initial velocity of the bullet is given by = = 400 m/s

and the initial velocity of the wooden block is given by = = 0 m/s

Now, the momentum conservation of law states that;

Momentum before collision = Momentum after collision

=

= = 4.4

So, v = 4.4 m/s which means this is the velocity acquired by the block.

ok chlo firr ek year ka wait krenge aapke 10th khtm hone ka

btw study hard