Physics, asked by prishajha186, 1 month ago

a bullet of mass 10 g strikes a sand bag at the speed of 1000 m/s and gets embedded after travelling 5 cm. calculate the resistive force exerted by sand on the bullet.

pls give answer STEP BY STEP with explanation.
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Answers

Answered by shreya17179
1

Answer:

t=-10⁴ seconds

Explanation:

Mass of bullet should be =10gm=0.01kg

initial velocity (U)of bullet=1000m/s

final velocity (V)=0m/s(because it has stopped after striking sand)

displacement of bullet=5cm=0.05m

a)using 2as=V ²-U²

2(a)(0.05)=0²-1000²

2a(5/100)=-1000000

2a(1/20)=-1000000

a(1/10)=-1000000

a=-10000000=-10^7

acceleration of bullet is -10^7=-10000000

by using F=ma

F=0.01(10000000)

F=1/100(10000000)

F=-100000N

there fore resistive force of bullet =-100000N

b)by using ,v=u+at

a=v-u/t

-10000000=0-1000/t

-10000000=-1000/t

-10000=t

or

t=-10⁴seconds

Answered by kdmondal1955
1

Answer:

This is your required answer.

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