A bullet of mass 10 g traveling at a speed of 500 m/s strikes a block of mass 2 kg, which is suspended by a string of length 5 m. The centre of gravity of the block is found to rise a vertical distance of 0.2 m. What is the speed of the bullet after it emerges from the block?
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Explanation:
Afther sfrike some energy is trasfere to bloels (2)(10)(0.2)=12(2)∪251004)2
4=V2bud
∫bbck=2m1s Guol nowntwa p0= Unock mbouk
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