Question

A bullet of mass 10 g travelling horizontally with a velocity of 200 m/sec strikes

a stationary wooden block and comes to rest in 0.04 sec. Calculate the distance of penetration of the

bullet into the block . Also , calculate the magnitude of the force exerted

by the wooden block on the bullet .​

Answer 1

~$\small \blue {\sf{Answer }}$✨❤

$Initial \: velocity \: of \: the \: bullet, \:  u=150 \:   ms−1 \\ </p><p></p><p>Final \: velocity \: of \: the \: bullet, \:   \\ </p><p></p><p>Mass \: of \: the \: bullet, \:  m=10  \: g=0.01 \:  kg \\ </p><p> </p><p>Time \: taken \: by \: the \: bullet \: to \: come \: to \: rest, t=0.03 s \: \\ </p><p></p><p>Let \: distance \: of \: penetration \: be  \: s \\ \\ </p><p></p><p></p><p>v=u+at \\ </p><p></p><p>0=150+a(0.03)   \\ </p><p></p><p>⟹a=−5000 ms−2    (- sign shows retardation) \\ </p><p></p><p></p><p>v2=u2+2as \\ </p><p></p><p>0=1502+2×(−5000)×s \\ </p><p></p><p>s=2.25 m \\ </p><p></p><p></p><p>Magnitude \: of \: the \: force \: exerted \: by \: the \: wooden \: block, ∣F \: ∣=m∣a∣ \\ </p><p></p><p>∣F∣=0.01×5000=50 N \\ </p><p></p><p>$