a bullet of mass 10 g travels horizontally with a speed of 100m/s and is absorbed by a wooden block of mass 990 g ,suspended by a strain ,find thye vertical height through which block rises
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Initial momentum of bullet+block system= 0.01×100 Kg-m/s.
Final momentum of the system
= (0.01+0.99)×v. ( where v is the final velocity after impact)
APPLYING LAW OF CONSERVATION OF LINEAR MOMENTUM :
0.01×100=(1)×v. we get v= 1m/s.
APPLYING LAW OF CONSERVATION OF MECHANICAL ENERGY :
(1/2)×(1)×(1)×(1)=(1)×g×h
(where g= acceleration due to gravity and h is the max height attained by bullet+block)
On solving we get h=0.05m
Final momentum of the system
= (0.01+0.99)×v. ( where v is the final velocity after impact)
APPLYING LAW OF CONSERVATION OF LINEAR MOMENTUM :
0.01×100=(1)×v. we get v= 1m/s.
APPLYING LAW OF CONSERVATION OF MECHANICAL ENERGY :
(1/2)×(1)×(1)×(1)=(1)×g×h
(where g= acceleration due to gravity and h is the max height attained by bullet+block)
On solving we get h=0.05m
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