A bullet of mass 10 g with speed 90 km/h hit a sand bag and entered 2 m into the
bag. Find out the time it takes to stop and its retardation force.
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Given:
A bullet of mass 10 g with speed 90 km/h hit a sand bag and entered 2 m into the bag.
To find:
Find out the time it takes to stop and its retardation force.
Solution:
From given, we have,
A bullet of mass 10 g with speed 90 km/h hit a sand bag and entered 2 m into the bag.
u = 90 km/hr = 25 m/s
we use the formulae,
v² = u² + 2as
0 = 25² + 2 × a × 2
0 = 625 + 4a
a = -156.25 m/s²
v = u + at
0 = 25 - 156.25 × t
t = 25/156.25
t = 0.16 s
F = ma
F = 10 × (-156.25)
F = -1562.5 N
Therefore, the time it takes to stop is 0.16 sand its retardation force is 1562.5N.
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