A bullet of mass 10 gm is fired vertically with a velocity of 100 m/s into a block of wood of inass 190 g suspended by a long string above the gun. If the builet is embedded in the block, through what height does the block move?
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Answer:
Here m=10g=102kg.
u1=100m/s,M=900g=9×10−1kg
u2=0,h=?g=10m/s2
If v is velocity of combination (bullet in block ), then from conservation of linear momentum,
(m+M)v=mu1+Mu2
=10−2×102+9×10−1×0
(10−2+9×10−1)v=1,v=1m/s
From (m+M)gh=12(m+M)v2
h=v22g==1×12×10m=5cm
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