Question

A bullet of mass 10 gm moving with 100 m/s is embedded in a block of 1 kg which is initially in rest.
The final velocity of the system will be​

Answer 1

AnswEr :

• The final velocity of the system will be 0.99m/s.

Given :

• Mass of bullet(M1) = 10 g = 0.01kg

• Mass of block(M2) = 1 kg

• Velocity of bullet(v1) = 100m/s

• Velocity of block(v2) = At rest = 0 m/s

To Find :

• Final velocity of the system(v) = ?

Concept Used :

We need to apply the law of conservation of momentum!!

Therefore,

Momentum before collision = Momentum after the collision .

Solution :

According to the law of conservation of momentum,

➝ M1× v1 + M2 × v2 = (M1 + M2)v

➝ 0.01 × 100 + 1 × 0 = (0.01 + 1)v

➝ 1 = 1.01 × v

➝ v = 1/1.01

➝ v = 0.99 m/s

$\therefore$ The final velocity of the system will be 0.99m/s.

⠀⠀━━━━━━━━━━━━

Something Interesting :

• Law of conservation of momentum is one of the powerful law in physics!!

• It states that :

For collision occurring between any 2 or more bodies or objects , the total momentum of the two objects or bodies before the collision is equal to the total momentum of the two objects after the collision.

★ More to be easy, in simple words just remember this :-

• Momentum before collision = Momentum after the collision

• Newton's cradle is an example of the Law of Conservation of Momentum.

⠀⠀━━━━━━━━━━━━