A bullet of mass 10 gm strikes a fixed target and penetrates 8cm into it. If the average resistance
offered by the target to the bullet is 100 N. The velocity with which the bullet hits the target is:
Answers
Answered by
6
Given ,
m=10gm
F=100N=0.01kgf
u=0
v=?
d=8cm
F=ma
a=F/m
a=0.01/10
a=1/100*10
a=0.001m/s^2
Therefore, v^2-u^2=2as
v^2-(0)^2=2*0.001*8
v^2=0.016
v=√0.016
v=0.12m/s
m=10gm
F=100N=0.01kgf
u=0
v=?
d=8cm
F=ma
a=F/m
a=0.01/10
a=1/100*10
a=0.001m/s^2
Therefore, v^2-u^2=2as
v^2-(0)^2=2*0.001*8
v^2=0.016
v=√0.016
v=0.12m/s
suganthiram:
This should have been the brainliest answer
Answer is 40 ms bro
Answered by
22
Distance,s = 8 cm = 0.08 m
u =?
v=0
force,F = -100N
mass= 10 gm = 0.01 kg
By 2nd law of motion
F=ma
-100=0.01×a
-100/0.01= a
a = -10000 m/s^2
By equation,
v^2-u^2=2as
0-u^2 =2×-10000×0.08
-u^2 = - 1600
u=40 m /s
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