Question

A bullet of mass 10 gm strikes a fixed target and penetrates 8cm into it. If the average resistanceoffered by the target to the bullet is 100 n. The velocity with which the bullet hits the target is:

Answer 1

Answer:

20 cm/s

According to conservation of mechanical energy :

K.E = P.E

1/2(m(v^(1/2)))=mas

2*100=1/2(v^(1/2))

v= 20 cm/s

Answer 2

K. E=P.E

1/2mv.^2=mgh

1/2*10*v^2=10*100*8

5v^2=8000

=v^2=8000/5

v^2=1600=√1600

=40

ans=40cm/s

hope it helps