Question

A bullet of mass 10 gram hits wooden block of mass 490 gram with a speed of 50 metre per second and sticks with it find the common speed of block plus Bullet by which name of together​

Answer 1

Answer:

Bullet and wooden blocks moves together  with a speed of 1 m/s

Explanation:

Mass of bullet   $m_{1}=10g=0.01 kg$

Mass of wooden block $m_{2}=490 g =0.49 kg$

Initial speed of bullet $u_{1}=50 m/s$

Initial speed of wooden block $u_{2}=0 m/s$

Bullet sticks to Wooden blocks and moves with a common speed v

From conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\m_{1}u_{1}+m_{2}u_{2}=v(m_{1}+m_{2})\\v=\frac{m_{1}u_{1}+m_{2}u_{2}}{(m_{1}+m_{2})} \\\\v=\frac{0.01 \times 50+0.49 \times 0}{0.01+0.49} \\\\v= 1 m/s$

Bullet and wooden blocks moves together  with a speed of 1 m/s