Question

A bullet of mass 10 gram is fired from a gun of mass 1 kg with recoil velocity of gun 5 metre per second the muscle velocity will be

Answer 1

Answer:

500 m/s

Explanation:

as per law of conservation of momentum,momentum will remain conserved in the system.

so, M1V1 = M2V2

10/1000* V= 1*5;

V = 5*1000/10

V =500 m/s.

Answer 2

The muscle velocity will be 500 m/s.

Explanation:

It is given that,

Mass of the bullet, m = 1 g = 0.01 kg

Mass of the gun, m' = 1 kg

Velocity of the gun, v' = 5 m/s

To find,

The velocity of the muscle.

Solution,

Let v is the velocity of the velocity of the muscle. It can be calculated using conservation of momentum as:

$mv+m'v'=0$

$mv=-m'v'$

$mv=-\dfrac{m'v'}{m}$

$v=-\dfrac{1\times 5}{0.01}$

v = 500 m/s

So, the muscle velocity will be 500 m/s. Hence, this is the required solution.

Learn more,

Conservation of momentum

https://brainly.in/question/5919548