Physics, asked by aryaabhisri6661, 11 months ago

A bullet of mass 10 gram is fired from a rifle with a speed of 3600km/h calculate the speed of the recoil of the rifle ,if its mass is 5kg

Answers

Answered by ShivamKashyap08
14

\huge{\bold{\underline{\underline{....Answer....}}}}

\huge{\bold{\underline{Given:-}}}

  • Mass of the bullet (m) = 10 grams,
  • Speed of bullet (u) = 3600 Km/h,
  • Mass of the gun(M) = 5 Kg.
  • Speed of the gun = v.

\huge{\bold{\underline{Explanation:-}}}

\rule{300}{1.5}

Firstly Converting the units in too S.I system,

10grams = ? Kg,

\large{\tt m = 1 \: gram = 0.001 \: kg}

Therefore,

\large{\tt \leadsto m = 10 \: grams = 10 \times 0.001 \: kg}

This implies,

\large{\boxed{\tt m = 0.01 \: kg}}

3600 Km/h = ? m/s.

\large{\tt u = 1 \: Km/h = \dfrac{5}{18} \: m/s}

\large{\tt \leadsto u = 3600 \: Km/h = 3600 \times \dfrac{5}{18} \: m/s}

\large{\tt \leadsto u = 3600 \: Km/h = \cancel{3600} \times \dfrac{5}{\cancel{18}} \: m/s}

This implies,

\large{\boxed{\tt u = 1000 \: m/s}}

\rule{300}{1.5}

\rule{300}{1.5}

From Law of Conservation of momentum

Statement:-

The momentum of body remains constant unless and until a net External Force is applied on it.

Now,

\large{\boxed{\tt P_i = P_f}}

Here,

  • {\tt P_i} = Initial momentum,
  • {\tt P_f} = Final momentum.

Here the whole system is at rest initially,

Therefore Initial momentum of the system will be Zero,

Therefore,

\large{\tt \leadsto 0 = Mv + mu}

Substituting the values,

\large{\tt \leadsto 0 = 5 \times v + 0.01 \times 1000}

\large{\tt \leadsto 0 = 5 \times v + \dfrac{1}{100} \times 1000}

\large{\tt \leadsto 0 = 5 \times v + \dfrac{1}{\cancel{100}} \times \cancel{1000}}

\large{\tt \leadsto 0 = 5v + 10}

\large{\tt \leadsto 5v = - 10}

\large{\tt \leadsto v = \dfrac{-10}{5}}

\large{\tt \leadsto v = \dfrac{\cancel{-10}}{\cancel{5}}}

\huge{\boxed{\boxed{\tt v = - 2 \: m/s}}}

So, The Recoil velocity of the Gun is - 2 m/s.

Note:-

  • Here the Negative Sign indicates that the Gun is moving in opposite direction that of the bullet.

\rule{300}{1.5}

Answered by omjayesh608gmailcom
1

Answer:

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