Question

A bullet of mass 10 gram is fired horizontally into 1 kg wooden block at rest on a horizontal surface the bullet remains constant in the block and the combination the bullet remains constant and the combination move 20m and it stop calculate the speed with which the bullet strike the block

Answer 1

Answer:

Mass of bullet, m = 0.01 kg

mass of wooden block, M = 4 kg

initial velocity of wooden block, u = 0

Let v be the velocity of system after bullet has entered into the block. the system comes to rest after covering a distance, s = 20m. Let a is the retardation produced by the system due to the frictional force, then

v² = u² + 2as

v² = 0 + 2 × 20 × a

v² = 40a.......(1)

the kinetic frictional force must be equal to retardation force.

e.g., (m + M)a = (m + M)g

or, a =

a = 0.25 × 10 = 2.5 m/s² , put it in equation (1),

v² = 40 × 2.5 = 100

=> v = 10 m/s

now use law of conservation of linear momentum for collision of bullet with the block.

so,

or,

= (0.01 + 4) × 10/0.01

= (4.01) × 1000

= 4010 m/s

hence, velocity of bullet is 4010 m/s

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