Question

A bullet of mass 10 gram is fired horizontally into 5 kg wooden block at rest on a horizontal surface the coefficient of kinetic friction between the block and surface is 0.1 calculate the speed of the bullet striking the block if the combination moves 20m. before coming to rest​

Answer 1

Heya mate... ❤️

m = 0.005 kg M = 1.500 kg

mu = 0.20

v = velocity of bullet before collision with the block

V = velocity of bullet + wooden block after bullet is embedded inside the block

Frictional force on the block = mu (m+M) g

Deceleration of the block = force / mass = mu * g = 0.20 * 9.8 m/sec²

a = - 1.96 m/sec²

v² - u² = 2 a s

=> 0² - V² = - 2 * 1.96 * 0.025

=> V = 0.313 m/s

Let apply conservation of linear momentum:

m v = (m + M) V

0.005 * v = 1.505 * 0.313

v = 94.22 m/sec

It is the same questions but the values are changed so this will help u to do this

Hope it helps uh ❤️