Question

A bullet of mass 10 gram is fired with a velocity of
300ms-1. Find its kinetic energy. ​

Answer 1

Answer:

4500J

Explanation:

Given,

m=0.1 kg

v=300m/s

KE=1/2×mv^2

=1/2×0.1x(300)^2

=4500J

Answer 2

Answer:

The kinetic energy of the bullet is equal to 4500Joules.

Explanation:

Given: The mass of the bullet $m=10g=1*10^{-3}Kg$

Bullet is fired with a velocity, $v=300ms^{-1}$

We know that the kinetic energy of  a body is due to its motion. The kinetic energy is equal to half times of mass of the body multiplied by square of its velocity.

Kinetic energy, $K.E.=\frac{1}{2}mv^{2}$

$K.E.=\frac{1}{2} (0.1Kg)(300ms^{-1})^{2}$

$K.E.=4500kgm^{2}s^{-2}$

$K.E.=4500J$

Therefore, the kinetic energy of bullet will be 4500J.