Question

A bullet of mass 10 gram is fixed from a gun of mass 6 kg with a velocity of 300 second calculate the recoil velocity of a gun​

Answer 1

Conservation of linear momentum gives,

m

1

v

1

+m

2

v

2

=0

m

1

v

1

=−m

2

v

2

v

1

=

m

1

−m

2

v

2

Given, m

1

=10g=(

1000

10

)kg,

m

2

=1 kg,

v

2

=−5m/s

∴v

1

=

10/1000

+1×5

or v

1

=500m/s.

Answer 2

Conservation of linear momentum gives,

m1v1+m2v2=0

m1v1=−m2v2

v1=m1−m2v2

Given, m1=10g=(100010)kg, 

m2=1 kg,

v2=−5m/s

∴v1=10/1000+1×5

or v1=500m/s.