Physics, asked by kavitakhedar82, 11 months ago

A bullet of mass 10 gram is horizontally fired with a velocity 150 metre per second from a pistol of mass 5kg the recoil velocity of the pistol will be

Answers

Answered by kingankitraj

2

Answer:

pls apply the formula m1u1+m1vi=m2u2+m2v2

you will get your ans

Answered by arsh122100

5

Answer:

by momentum formula

m1v1=m2v2

10*150=5/1000*v2

(1500*1000)/5=v2

v2=15000/5=3000

or 3000/1000=3km/h

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