Question

A bullet of mass 10 gram moving with a velocity of 400 m per second get embedded in a free suspended

Answer 1

pls complete your question

Answer 2

Initial momentum of the bullet = 10 g Х 400 m/s = 4000 g m/s

Initial momentum of the block = 700 g Х 0 = 0

Total momentum of the system before collision = 4000 g m/s

 

Let the velocity of the block after collision be v. As the bullet and the block move together the mass of the system is = 10 + 700 = 710 g

Momentum of the system after collision = 710 g Х v

 

Applying the law of conservation of momentum,

4000 g m/s = 710 g Х v

Implies, v = (4000/710) = 5.633 m/s

 

Hope this helps,