Question

A bullet of mass 10 gram moving with a velocity of 400 metre per second get embedded in a freely suspended wooden block of mass 900 gram what is the velocity acquired by block?​

Answer 1

Answer:

4.4m/s

Explanation:

mass of bullet= 10 g = 0.01 kg

velocity of bullet=400 m/s

mass of wooden box= 900 g =0.9 kg

velocity of wooden block= ?

formula= Mb 1*Vb 1=Mb 2*Vb 2

0.01*400=0.9*Vb2

=0.01*400/0.9=4.4444444 m/s

ans=4.4 m/s

Answer 2

Answer:

According to the law of conservation of momentum,

m1×v1=m2×v2

10×400=900×v2

v2=4000/900

v2=40/9

Velocity of block = 4.45 meter per second