A bullet of mass 10 gram moving with velocity v 50 m second come to the rest after penetrating 40 centimetre in a wooden block find resistive force
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given,
mass of the bullet(m) = 10gm=0.01kg
initial velocity(u)=50m/s
final velocity(v)=0 m/s
distance(s) =40cm=0.4m
we know that,
v²=u²+2as
0=50²+2a*0.4
-2500=2a*0.4
-2500=0.8a
a=-2500/0.8
a=3125m/s²
resistive force (f) = ma
f=0.01*3125
f=31.25N
mass of the bullet(m) = 10gm=0.01kg
initial velocity(u)=50m/s
final velocity(v)=0 m/s
distance(s) =40cm=0.4m
we know that,
v²=u²+2as
0=50²+2a*0.4
-2500=2a*0.4
-2500=0.8a
a=-2500/0.8
a=3125m/s²
resistive force (f) = ma
f=0.01*3125
f=31.25N
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