Question

A bullet of mass 10 gram travelling horizontally with a velocity of 150 M per second strikes a stationary wooden block and comes to rest in 0.03 seconds calculate the distance of penetration
of the bullet into the block also calculate the magnitude of force by wooden block of the bullet​

Answer 1

Hey friend..

Here is the answer..

m=10 g = 0.01 kg

u=150 m/s

v=0

t= 0.03s

   

a=v-u/t

 =0-150/0.03 =5000 m/s²

S= ut + 1/2 at²

   = 150 ×0.03 + 1/2 × 0.03× 0.03

   =2.25 m

F=ma

 0.01 × 5000 = 50 N

Hope it helps you!

Answer 2

ur answer is attached.......