a bullet of mass 10 grams moving with a velocity of 400m /sec gets embedded in a freely suspended in wooden block of mass 900gm what is the velocity accuses by the block
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hi,
mass of bullet = 1/100 g
velocity=400m/s
mass of block=900g
m1u1=m2u2 consevation of liner momentum
1/100x400=910/1000xV2
4=91/100xV2
400/91=V2
V2=4.395M/S
mass of bullet = 1/100 g
velocity=400m/s
mass of block=900g
m1u1=m2u2 consevation of liner momentum
1/100x400=910/1000xV2
4=91/100xV2
400/91=V2
V2=4.395M/S
maithilimundle:
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