Question

A bullet of mass 100 g is moving with a speed of 200 ms-1. what is the K.E of bullet?

Answer 1

K. E. = 1/2×Mass×(Velocity)square
=1/2x0.1x200
=10

Answer 2

Kinetic Energy = k

Mass of object = m

Speed of object = v

Therefore,

 k = $\frac{1}{2}$m$v^{2}$

    = $\frac{1}{2}$ x 100 x $(200)^{2}$

    = 200 J