Question

A bullet of mass 100 g moving with a velocity of 250 m/s hits a block of mass 2 kg resting on a smooth table. It comes out with a speed of 150 m/s. The block moves with a velocity of __ m/s.

Answer 1

Given :  A bullet of mass 100 g moving with a velocity of 250 m/s hits a block of mass 2 kg resting on a smooth table. It comes out with a speed of 150 m/s.

To Find : The block moves with a velocity of __ m/s.

Solution:

Conservation of momentum :

Initial Momentum

= (100/1000) * 250  + 2 * 0

= 25  kg m/s

Final Momentum  = 25 kg m/s

2 * v +  (100/1000)150  = 25

=> 2v  + 15 = 25

=> 2v = 10

=> v = 5

The block moves with a velocity of 5  m/s.  

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Answer 2

HELLO DEAR,

GIVEN:-;Mass of bullet = 100g

= 0.1 kg

Velocity of bullet = 250m/s

Mass of wooden block = 2 kg

To find the velocity of block when bullet penetrate the block and come out with a velocity of 150 m/s.

SOLUTION:-

By using conservation of momentum

initial momentum = final momentum

(0.1 × 250) + ( 2 × 0) = ( 0.1 × 150) + ( 2 × v)

25 = 15 + 2v

2v = 10

v = 10/2

v = 5 m/s.

v= 5 m/s.

I HOPE IT'S HELP YOU DEAR,

THANKS.