Question

A bullet of mass 100 g moving with a velocity of 300 ms strikes a wall and goes out of the other side with a velocity of 100 ms- Calculate work done in passing through the wall​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

A bullet of mass 100 g moving with a velocity of 300 m/s strikes a wall and goes out of the other side with a velocity of 100 m/s. The work done in passing through the wall is, 4000 J.

Explanation:

We know,

        Work done  =  Change in kinetic energy  

        Let,  $\mathrm{KE}_{1}$ be the kinetic energy of bullet before hitting the wall and $\mathrm{KE}_{2}$ be the kinetic energy of the bullet after hitting the wall.

                           Work done = $\mathrm{KE}_{2}-\mathrm{KE}_{1}$

       If $\mathrm {V}_{1}$ and ${V}_{2}$ are the velocity of bullet before hitting the wall and after hitting the wall and 'm' is mass of the  bullet,

                  $\text { Work done } (W)=\mathrm{KE}_{2}-\mathrm{KE}_{1} = \frac{1}{2} m v_{1}^{2} - \frac{1}{2} m_{} v_{2}^{2}$  

                                  ( Since $K E = \frac{1}{2} m_{} v_{}^{2}$ )

Given ,

                       m = 100g = $\frac{100}{1000} = 0.1 kg$

                       $V_{1} = 300 m/s\\V_{2} = 100 m/s$

                       $W = \frac{1}{2} m (v_{1}^{2} - v_{2}^{2} )$

                            $= \frac{1}{2}\times 0.1\times (300^{2} - 100^{2} )$

                             =  4000J